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voltage drop calulations (academic exercise)

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raymondj(at)frontiernet.n
Guest

Posted: Tue Feb 26, 2008 7:59 pm Post subject: voltage drop calulations (academic exercise)

Bob,



Academic exercise question.



Why does the resistance in the return path (assuming DC and resistive load 

element) affect the voltage seen by the element being provided power?  Or am 

I thinking '60 British (positive ground).



Thanks in advance,

Raymond Julian

Kettle River, MN



"Hope for the best,

but prepare for the worst."



do not archive

---

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rjquillin

Joined: 13 May 2007
Posts: 123
Location: KSEE

Posted: Tue Feb 26, 2008 9:17 pm Post subject: voltage drop calulations (academic exercise)

Because the load 'sees' the supply voltage referenced to it's, the

load's, local ground.  If the local ground isn't really 'ground', that

there is a voltage differential between 'true' ground and local ground

caused by ground currents, the local ground is offset by that voltage

from the true supply ground.  So the actual supply voltage the load

sees is reduced by the voltage in the return path and the load doesn't

really see the full supply voltage, as it is reduced by losses in both

the supply and return wiring.  It's all just like a resistor in series

with the supply, be it in either conductor.



 	  Quote: 	
		    Why does the resistance in the return path (assuming DC and resistive load

  element) affect the voltage seen by the element being provided power?  Or am

  I thinking '60 British (positive ground).

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raymondj(at)frontiernet.n
Guest

Posted: Tue Feb 26, 2008 11:48 pm Post subject: voltage drop calulations (academic exercise)

Ron,



    So,  the circuit is functionally 3 resistors in series and the middle 

resistor (load) can only see the voltage drop across it as part of the total 

voltage drop in the entire circuit. If that's correct than I understand.



Thanks for the explanation.

Raymond Julian

Kettle River, MN



"Hope for the best,

but prepare for the worst."

---

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