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Angle of Bank vs Stall Speed

 
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kuffel(at)cyberport.net
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PostPosted: Wed Apr 28, 2010 12:55 pm    Post subject: Angle of Bank vs Stall Speed Reply with quote

Sent this two hours ago. So far it hasn't appeared on the list. My paranoid side says there must be censorship of my ideas somewhere.

-----------------------------------------------------------------

Sigh. My conscience won't let me ignore this.

pj, boyd, Dana:

Dang it, ignore what I say, fly the maneuver and see for yourself. Go to
altitude, reduce power if you wish, enter a 30 degree bank and hold
absolutely constant airspeed for 180 degrees and then roll level. Repeat at
5 miles/knots slower. Repeat again until you are as close to Vso as your
ability to hold a constant airspeed allows. You will not stall.

For more details as to why this is true review my messages in the thread
linked by Jason:

[url=]http://forums.matronics.com/viewtopic.php?t=38477&highlight=descending+turn+stall[/url]

Now:

<< If the turns are less than 30 deg and the g load less than 1.5,, you
may be ok. if the turn is 60 or more deg bank and g load 2 or above >>

<< In a coordinated turn, the stall speed increases as a function of the
bank angle >>

These out of context statements are exactly the misconception which kills
pilots every year. I know, it almost killed me during my primary training.
I know, base to final turn accidents are a major source of aircraft
fatalities every year. They are true *if you maintain (approximately) a
constant vertical component for your lift vector.* The only way to do this
is to increase your total lift, in other words maintain constant altitude,
in other words increase your load factor.

But don't believe me, go out and fly the maneuver yourself at altitude.

Look at the AIM diagram we have all had drummed into our subconscious. As
the angle of bank increases, the total lift increases to keep the vertical
component the same. Now with your hands block out all but the first
airplane. Rotate the entire manual. This is the case of a constant
airspeed in a turn. Some of the lift is now used to make the turn and less
lift is available to oppose gravity and you will *start* to descend faster.
But since the total lift is unchanged so is the stall speed. In other
words, stall speed increases with load factor, not angle of bank.

But don't believe me, go out and fly the maneuver yourself at altitude.

<< Take a 45 degree bank, for example. In a normal, coordinated, level
turn, you pull 1.41G. If you put your aircraft into a 45 degree bank and
hold 1G, the vertical component of lift will be only 0.707g; thus you'll
have a downward acceleration of 0.3g, or 9.4 ft/s/s, or 566 fpm/s. This
means that after one second, your rate of descent will have increased by 566
fpm. After four seconds, you're descending at 2264 fpm, which is a pretty
steep dive, and you WILL pull more than one g pulling out of it. >>

The math here is wrong. After one second you are descending at 9 feet/sec,
2 seconds you are now at 19 ft/sec, 3 seconds = 28 ft/sec, 4 sec = 38 ft/sec
or so. In addition it ignores the vertical component of drag which is
significant.

But don't believe me, go out and fly the maneuver yourself at altitude.

The above statements as well as the "death spiral" of Boyd's CFI are the
result of misunderstanding the context of what I and others are trying to
fix. The problem is the turn from base to final. Most pilots initiate a
bank of about 30 degrees. Half way through the turn they see they are
overshooting the runway. What they should do is increase their angle of
bank to 45 degrees or even briefly 60 degrees at constant airspeed to finish
the turn. Instead, because "increased angle of bank means increased stall
speed" (in a different context) has been fixated in their minds they try to
fudge the situation with rudder and/or tightening up (pulling on the stick)
instead. This brings them to experience the other four fundamentals of
flight: stall, spin, crash and burn. What we must fixate instead is
"constant airspeed = constant load factor = constant stall speed".

But don't believe me, go out and fly the maneuver yourself at altitude.

Now just because I have an evil nature let me mention one more context
besides turns at low altitude for landing. This should start another thread
in the Seafoam mode. The concept of constant airspeed control is also
paramount in mountain search and rescue reversing turns and box canyon
escapes. What I teach is no change in power, smoothly increase your climb
rate and bank until you reach your desired bank and airspeed, say Vs1 + 10.
Maintain this bank and airspeed until you have reversed direction. You will
now be in a decent but at a higher altitude, smoothly pullout and you are
now going in the opposite direction at roughly your starting altitude and
airspeed. This method allows the pilot to concentrate on airspeed control
and situational awareness without the distraction of power control. The
reduced airspeed during the turn also creates a very small radius of turn.

But don't believe me, go out and fly the maneuver yourself at altitude.

Let me finish with an irrelevant appeal to authority. Every, and I mean
every, CFI with whom I've had the above discussion and then taken flying has
adopted my emphasis on constant airspeed control for maneuvering close to
the ground.

But don't believe me, go out and fly the maneuver yourself at altitude.

Good luck and have fun,

Tom Kuffel, CFI
EAA Flight Advisor

[quote][b]


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Dana



Joined: 13 Dec 2007
Posts: 1047
Location: Connecticut, USA

PostPosted: Thu Apr 29, 2010 12:21 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

At 04:39 PM 4/28/2010, The Kuffels wrote:


Quote:
For more details as to why this is true review my messages in the thread
linked by Jason:

[url=??]http://forums.matronics.com/viewtopic.php?t=38477&highlight=descending+turn+stall[/url]

I did. I stand by what I said there, as well as in this thread.

Quote:
<< In a coordinated turn, the stall speed increases as a function of the
bank angle >>

Correct.

Quote:
true *if you maintain (approximately) a
constant vertical component for your lift vector.* The only way to do this
is to increase your total lift, in other words maintain constant altitude,
in other words increase your load factor.

Correct. Note that if you don't maintain "a constant vertical vertical component for your lift vector", you will accelerate downward (or upward, as the case may be, though that's not what we're talking about).

Quote:
...This is the case of a constant
airspeed in a turn. Some of the lift is now used to make the turn and less
lift is available to oppose gravity and you will *start* to descend faster.
But since the total lift is unchanged so is the stall speed. In other
words, stall speed increases with load factor, not angle of bank.

Correct. "You will *start* to descend faster." And if you maintain 1G in a banked turn, you will *continue* to accelerate downward.

Quote:
<< Take a 45 degree bank, for example. In a normal, coordinated, level
turn, you pull 1.41G. If you put your aircraft into a 45 degree bank and
hold 1G, the vertical component of lift will be only 0.707g; thus you'll
have a downward acceleration of 0.3g, or 9.4 ft/s/s, or 566 fpm/s. This
means that after one second, your rate of descent will have increased by 566
fpm. After four seconds, you're descending at 2264 fpm, which is a pretty
steep dive, and you WILL pull more than one g pulling out of it. >>

The math here is wrong. After one second you are descending at 9 feet/sec,
2 seconds you are now at 19 ft/sec, 3 seconds = 28 ft/sec, 4 sec = 38 ft/sec
or so. In addition it ignores the vertical component of drag which is
significant.

What math do you say is wrong? Sounds like you're agreeing with me, as I said after one second you're descending at 9.4 ft/s, etc. You rounded the numbers off but they're approximately the same as mine (after four seconds, 38 ft/s is 2280 fpm).

The vertical component of drag is zero at the start, and then yes, it becomes significant. However, it doesn't affect the math, because regardless of the drag, you _have_ to accelerate downward as described above or you won't maintain 1G.

Quote:
...Half way through the turn they see they are
overshooting the runway. What they should do is increase their angle of
bank to 45 degrees or even briefly 60 degrees at constant airspeed to finish
the turn. Instead, because "increased angle of bank means increased stall
speed" (in a different context) has been fixated in their minds they try to
fudge the situation with rudder and/or tightening up (pulling on the stick)
instead...

Both are the wrong thing to do. Increase the bank angle in coordinated turn and you risk an acelerated stall; add rudder for a skidding turn and you risk stalling the inside wing.

Quote:
What we must fixate instead is
"constant airspeed = constant load factor = constant stall speed".

Constant load factor = constant stall speed, yes. Constant airspeed has nothing to do with it.

Don't get me wrong; i understand (or I think I understand) the technique you're advocating: steepen the turn but don't pull back, instead letting the airplane fall off into a descent. But saying that you're OK if you maintain a constant airspeed is fixating on one aspect of the problem, and can get a pilot into trouble. Fly at 1.3Vs and enter a 60 degree coordinated turn and you either get an accelerated stall, or end up in a dive which also requires more than 1G to pull out.

"But don't believe me," do the math yourself.

-Dana

P.S. A conventional pitot tube airspeed indicator is only accurate when the pitot tube is aligned with the airflow. At high AOA, the airspeed indicator will read less than the actual airspeed, i.e. you're actually going faster than you think you are... which may explain why you're not stalling even when the indicated airspeed is less than the stall speed corresponding to the load factor corresponding to the bank angle.

"But don't believe me," do the math yourself.

--
Life is a sexually transmitted disease. [quote][b]


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slyck(at)frontiernet.net
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PostPosted: Thu Apr 29, 2010 2:25 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

Good stuff Tom. Can't say I've studiously done exactly what you describe but sounds 100%.In my younger and bolder days, on occasion I used a method to bleed altitude that I would not recommend:
not S turning, not slipping, not the Kolb dive...
I would, on a high final, deliberately stall the old crate, or pretty close to it. Sure would lose a lot of altitude
and the wings would stay nice and level. Then I'd toss a touch of throttle at it and squeak it on nice and short.
Obviously this would be solo. Gusty conditions would be a no no, as would hedgerows or any extraneous
turbulizers. Very exhilarating. Last time I did it for funsies was on a near zero day in a field near where a neighbor
was operating a McCulloch J2 gyrocopter. I siloed it a touch too aggressively and bent a few tubes
and cracked the windshield. It needed a new one anyway. Only landing I did that short after that was
with a power failure in a neighbor's champ on take off with nothing good ahead. (wires and houses)
Silo descent to plowed ground aside the runway. Zero roll out. No damage. Old neighbor never asked me to fly his
areoplane again though.
I wouldn't try it in my Kolb. Too old. Back might break.
BB


On 28, Apr 2010, at 4:39 PM, The Kuffels wrote:
Quote:
Sent this two hours ago. So far it hasn't appeared on the list. My paranoid side says there must be censorship of my ideas somewhere.

-----------------------------------------------------------------

Sigh. My conscience won't let me ignore this.

pj, boyd, Dana:

Dang it, ignore what I say, fly the maneuver and see for yourself. Go to
altitude, reduce power if you wish, enter a 30 degree bank and hold
absolutely constant airspeed for 180 degrees and then roll level. Repeat at
5 miles/knots slower. Repeat again until you are as close to Vso as your
ability to hold a constant airspeed allows. You will not stall.

For more details as to why this is true review my messages in the thread
linked by Jason:

[url=]http://forums.matronics.com/viewtopic.php?t=38477&highlight=descending+turn+stall[/url]

Now:

<< If the turns are less than 30 deg and the g load less than 1.5,, you
may be ok. if the turn is 60 or more deg bank and g load 2 or above >>

<< In a coordinated turn, the stall speed increases as a function of the
bank angle >>

These out of context statements are exactly the misconception which kills
pilots every year. I know, it almost killed me during my primary training.
I know, base to final turn accidents are a major source of aircraft
fatalities every year. They are true *if you maintain (approximately) a
constant vertical component for your lift vector.* The only way to do this
is to increase your total lift, in other words maintain constant altitude,
in other words increase your load factor.

But don't believe me, go out and fly the maneuver yourself at altitude.

Look at the AIM diagram we have all had drummed into our subconscious. As
the angle of bank increases, the total lift increases to keep the vertical
component the same. Now with your hands block out all but the first
airplane. Rotate the entire manual. This is the case of a constant
airspeed in a turn. Some of the lift is now used to make the turn and less
lift is available to oppose gravity and you will *start* to descend faster.
But since the total lift is unchanged so is the stall speed. In other
words, stall speed increases with load factor, not angle of bank.

But don't believe me, go out and fly the maneuver yourself at altitude.

<< Take a 45 degree bank, for example. In a normal, coordinated, level
turn, you pull 1.41G. If you put your aircraft into a 45 degree bank and
hold 1G, the vertical component of lift will be only 0.707g; thus you'll
have a downward acceleration of 0.3g, or 9.4 ft/s/s, or 566 fpm/s. This
means that after one second, your rate of descent will have increased by 566
fpm. After four seconds, you're descending at 2264 fpm, which is a pretty
steep dive, and you WILL pull more than one g pulling out of it. >>

The math here is wrong. After one second you are descending at 9 feet/sec,
2 seconds you are now at 19 ft/sec, 3 seconds = 28 ft/sec, 4 sec = 38 ft/sec
or so. In addition it ignores the vertical component of drag which is
significant.

But don't believe me, go out and fly the maneuver yourself at altitude.

The above statements as well as the "death spiral" of Boyd's CFI are the
result of misunderstanding the context of what I and others are trying to
fix. The problem is the turn from base to final. Most pilots initiate a
bank of about 30 degrees. Half way through the turn they see they are
overshooting the runway. What they should do is increase their angle of
bank to 45 degrees or even briefly 60 degrees at constant airspeed to finish
the turn. Instead, because "increased angle of bank means increased stall
speed" (in a different context) has been fixated in their minds they try to
fudge the situation with rudder and/or tightening up (pulling on the stick)
instead. This brings them to experience the other four fundamentals of
flight: stall, spin, crash and burn. What we must fixate instead is
"constant airspeed = constant load factor = constant stall speed".

But don't believe me, go out and fly the maneuver yourself at altitude.

Now just because I have an evil nature let me mention one more context
besides turns at low altitude for landing. This should start another thread
in the Seafoam mode. The concept of constant airspeed control is also
paramount in mountain search and rescue reversing turns and box canyon
escapes. What I teach is no change in power, smoothly increase your climb
rate and bank until you reach your desired bank and airspeed, say Vs1 + 10.
Maintain this bank and airspeed until you have reversed direction. You will
now be in a decent but at a higher altitude, smoothly pullout and you are
now going in the opposite direction at roughly your starting altitude and
airspeed. This method allows the pilot to concentrate on airspeed control
and situational awareness without the distraction of power control. The
reduced airspeed during the turn also creates a very small radius of turn.

But don't believe me, go out and fly the maneuver yourself at altitude.

Let me finish with an irrelevant appeal to authority. Every, and I mean
every, CFI with whom I've had the above discussion and then taken flying has
adopted my emphasis on constant airspeed control for maneuvering close to
the ground.

But don't believe me, go out and fly the maneuver yourself at altitude.

Good luck and have fun,

Tom Kuffel, CFI
EAA Flight Advisor

Quote:


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PostPosted: Thu Apr 29, 2010 2:50 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

From: "The Kuffels" <kuffel(at)cyberport.net>
Date: Wed, 28 Apr 2010 14:39:28 -0600
Quote:

Sigh. My conscience won't let me ignore this.

........
Quote:


Tom,

Sounds like you are advocating flying a powered aircraft much like flying a
glider or sailplane. Sailplane instructors emphasize coordinated turns and
constant speed and never mention constant altitude. When I started flying
sailplanes, one of the things I had to unlearn was the desire to maintain
altitude through out a turn, and learn to fly at constant speed. You are
correct in that I never fell into a spin while thermalling while flying at
constant speed no matter how steep the bank or the speed.

With an engine as the energy source, one can easily recover any altitude lost after a constant speed turn. I believe it is a less stressful way to fly on both the pilot and the machine, since one does not have make power changes during a turn to maintain constant altitude.

Thanks.

Jack B. Hart FF004
Winchester, IN


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PostPosted: Thu Apr 29, 2010 9:49 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

Sigh. My conscience won't let me ignore this.

pj, boyd, Dana:

Dang it, ignore what I say, fly the maneuver and see for yourself. Go to
altitude, reduce power if you wish, enter a 30 degree bank and hold
absolutely constant airspeed for 180 degrees and then roll level. Repeat at
5 miles/knots slower. Repeat again until you are as close to Vso as your
ability to hold a constant airspeed allows. You will not stall.

For more details as to why this is true review my messages in the thread
linked by Jason:

http://forums.matronics.com/viewtopic.php?t=38477&highlight=descending+turn+stall

Now:

<< If the turns are less than 30 deg and the g load less than 1.5,, you
may be ok. if the turn is 60 or more deg bank and g load 2 or above >>

<< In a coordinated turn, the stall speed increases as a function of the
bank angle >>

These out of context statements are exactly the misconception which kills
pilots every year. I know, it almost killed me during my primary training.
I know, base to final turn accidents are a major source of aircraft
fatalities every year. They are true *if you maintain (approximately) a
constant vertical component for your lift vector.* The only way to do this
is to increase your total lift, in other words maintain constant altitude,
in other words increase your load factor.

But don't believe me, go out and fly the maneuver yourself at altitude.

Look at the AIM diagram we have all had drummed into our subconscious. As
the angle of bank increases, the total lift increases to keep the vertical
component the same. Now with your hands block out all but the first
airplane. Rotate the entire manual. This is the case of a constant
airspeed in a turn. Some of the lift is now used to make the turn and less
lift is available to oppose gravity and you will *start* to descend faster.
But since the total lift is unchanged so is the stall speed. In other
words, stall speed increases with load factor, not angle of bank.

But don't believe me, go out and fly the maneuver yourself at altitude.

<< Take a 45 degree bank, for example. In a normal, coordinated, level
turn, you pull 1.41G. If you put your aircraft into a 45 degree bank and
hold 1G, the vertical component of lift will be only 0.707g; thus you'll
have a downward acceleration of 0.3g, or 9.4 ft/s/s, or 566 fpm/s. This
means that after one second, your rate of descent will have increased by 566
fpm. After four seconds, you're descending at 2264 fpm, which is a pretty
steep dive, and you WILL pull more than one g pulling out of it. >>

The math here is wrong. After one second you are descending at 9 feet/sec,
2 seconds you are now at 19 ft/sec, 3 seconds = 28 ft/sec, 4 sec = 38 ft/sec
or so. In addition it ignores the vertical component of drag which is
significant.

But don't believe me, go out and fly the maneuver yourself at altitude.

The above statements as well as the "death spiral" of Boyd's CFI are the
result of misunderstanding the context of what I and others are trying to
fix. The problem is the turn from base to final. Most pilots initiate a
bank of about 30 degrees. Half way through the turn they see they are
overshooting the runway. What they should do is increase their angle of
bank to 45 degrees or even briefly 60 degrees at constant airspeed to finish
the turn. Instead, because "increased angle of bank means increased stall
speed" (in a different context) has been fixated in their minds they try to
fudge the situation with rudder and/or tightening up (pulling on the stick)
instead. This brings them to experience the other four fundamentals of
flight: stall, spin, crash and burn. What we must fixate instead is
"constant airspeed = constant load factor = constant stall speed".

But don't believe me, go out and fly the maneuver yourself at altitude.

Now just because I have an evil nature let me mention one more context
besides turns at low altitude for landing. This should start another thread
in the Seafoam mode. The concept of constant airspeed control is also
paramount in mountain search and rescue reversing turns and box canyon
escapes. What I teach is no change in power, smoothly increase your climb
rate and bank until you reach your desired bank and airspeed, say Vs1 + 10.
Maintain this bank and airspeed until you have reversed direction. You will
now be in a decent but at a higher altitude, smoothly pullout and you are
now going in the opposite direction at roughly your starting altitude and
airspeed. This method allows the pilot to concentrate on airspeed control
and situational awareness without the distraction of power control. The
reduced airspeed during the turn also creates a very small radius of turn.

But don't believe me, go out and fly the maneuver yourself at altitude.

Let me finish with an irrelevant appeal to authority. Every, and I mean
every, CFI with whom I've had the above discussion and then taken flying has
adopted my emphasis on constant airspeed control for maneuvering close to
the ground.

But don't believe me, go out and fly the maneuver yourself at altitude.

Good luck and have fun,

Tom Kuffel, CFI
EAA Flight Advisor


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PostPosted: Thu Apr 29, 2010 1:56 pm    Post subject: Angle of Bank vs Stall Speed Reply with quote

Kolbers,

Viewed Richard Pike's recommended video yesterday evening. For those of you
with out a high speed Internet connection, I recorded the data, and here it
is. C 172 flying at a constant 65 ias making full 360 degree coordinated
turns.

Bank Lost Decent
Angle Altitude Rate
(deg) (feet) (fpm)
15 879 600
30 450 650
45 390 900
60 350 1500

The video displayed the instrument panel. The rate of decent did not
increase during the turn. The stall horn came on during the 45 degree bank
but there was no buffeting. There was some buffeting during the 60 degree
bank, but no stall horn.

Also the performed some 180 emergency turn arounds by setting their
altimeter to zero at 100 feet agl. They flew the airport runway at 100 ft
agl and initiated a climb at over the runway and climbed to 600 feet agl and
pulled the throttle. They could not get back to the airport using a 15
degree bank.

Good video!

Jack B. Hart FF004
Winchester, IN


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PostPosted: Thu Apr 29, 2010 8:30 pm    Post subject: Angle of Bank vs Stall Speed Reply with quote

Dana said:

<< << In a coordinated turn, the stall speed increases as a function of the
bank angle >>

Correct. >>

Not correct. This is only true in the special circumstance of maintaining altitude, ie increasing total lift, aka load factor. The emphasis on this without equal emphasis on the special circumstance is *why* pilots in the stress of landing still stall by trying to increase their rate of turn with rudder alone (uncoordinated flight) and/or pulling back (increasing load factor). The certain antidote to this error is constant airspeed during landing maneuvers.

Once again, go up in the air and test my statements. I don't dispute holding a constant airspeed in a turn will increase your rate of decent. But we are not talking about turns which last for minutes or even more than a few seconds. I strongly dispute the notion that any technique other than constant airspeed and coordinated flight independent of (less than aerobatic) bank angle is the proper way to avoid problems during the turn from base to final, particularly in situations of no or steady power or practicing same, which should be almost always.

Boyd said:

<< I had given an example of a steep bank turn to emphasize the situation.
And my definition of 1 g plus is 1.01g and above. I am probably taking
things to literally. >>

Not really. I wasn't worried about 1 g +/- 10% or so. The problem is the emphasis on bank angle materially increasing stall speed (I call double a material increase) without equal emphasis that the real cause is via increased load factor, and that this doesn't apply in a descending turn has resulted in pilots killing themselves year after year in the turn to final. And the absolutely, positively sure way to not increase load factor in this turn is constant airspeed.

<< Any time you turn a plane there is going to be more energy required. And
you can trade the energy needed to turn by unloading the wings momentarily
and remain at a literal 1g . But as soon as the plane returns to a steady
state and you remain in a turn, greater than 1g will be required. >>

This is not true. The lift vector on the wings has no idea what the gravity vector is doing. Go up and set a bank angle of 20 degrees and constant airspeed. You will find yourself in a steady state turn of 1 g. What will also happen is your rate of decent will increase. But this decent is not in a vacuum. The increase in your decent is actually slowed by the air such that several full circles are easily possible.. I've demonstrated this many times for people, even disbelieving fellow CFIs. (Are CFIs really people?) Now when doing the same thing at 60 degree bank things get real exciting very soon, even at only 1/4 circle, which may be Dana's point. But my point is this fact doesn't apply to the problem, its cause or the proper solution to avoid it.

Tom Kuffel
[quote][b]


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rickofudall



Joined: 19 Sep 2009
Posts: 1392
Location: Udall, KS, USA

PostPosted: Fri Apr 30, 2010 3:37 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

This always turns (pardon me) into such a lively discussion about angles, constant speeds and gee loads and then somebody finally says something like,

"What will also happen is your rate of decent will increase"


and we get to the true crux of the matter. Something had to give among all these constants and it seems to be that the ground will come up at a faster rate to smite thee. How about that. 
I read somewhere that there was a sign in the Curtiss Flying School office that said, "Flying is simple, to go up pull back on the stick. To come down, pull back farther". That was around 100 years ago and seems to be, amazingly enough, still true today.


Rick

On Thu, Apr 29, 2010 at 11:25 PM, The Kuffels <kuffel(at)cyberport.net (kuffel(at)cyberport.net)> wrote:
[quote] Dana said:
 
<<    << In a coordinated turn, the stall speed increases as a function of the
bank angle >>

Correct.  >>
 
Not correct.  This is only true in the special circumstance of maintaining altitude, ie increasing total lift, aka load factor.  The emphasis on this without equal emphasis on the special circumstance is *why* pilots in the stress of landing still stall by trying to increase their rate of turn with rudder alone (uncoordinated flight) and/or pulling back (increasing load factor).  The certain antidote to this error is constant airspeed during landing maneuvers.
 
Once again, go up in the air and test my statements.  I don't dispute holding a constant airspeed in a turn will increase your rate of decent.  But we are not talking about turns which last for minutes or even more than a few seconds.   I strongly dispute the notion that any technique other than constant airspeed and coordinated flight independent of (less than aerobatic) bank angle is the proper way to avoid problems during the turn from base to final, particularly in situations of no or steady power or practicing same, which should be almost always.
 
Boyd said:
 
<<  I had given an example of a steep bank turn to emphasize the situation.
And my definition of 1 g plus   is 1.01g and above.   I am probably taking
things to literally.  >>
 
Not really.  I wasn't worried about 1 g +/- 10% or so.  The problem is the emphasis on bank angle materially increasing stall speed (I call double a material increase) without equal emphasis that the real cause is via increased load factor, and that this doesn't apply in a descending turn has resulted in pilots killing themselves year after year in the turn to final.  And the absolutely, positively sure way to not increase load factor in this turn is constant airspeed.

<<   Any time you turn a plane there is going to be more energy required.  And
you can trade the energy needed to turn by unloading the wings momentarily
and remain at a literal 1g .   But as soon as the plane returns to a steady
state and you remain in a turn,  greater than 1g will be required. >>
 
This is not true.  The lift vector on the wings has no idea what the gravity vector is doing.  Go up and set a bank angle of 20 degrees and constant airspeed.  You will find yourself in a steady state turn of 1 g.  What will also happen is your rate of decent will increase.  But this decent is not in a vacuum.  The increase in your decent is actually slowed by the air such that several full circles are easily possible..  I've demonstrated this many times for people, even disbelieving fellow CFIs. (Are CFIs really people?)  Now when doing the same thing at 60 degree bank things get real exciting very soon, even at only 1/4 circle, which may be Dana's point.  But my point is this fact doesn't apply to the problem, its cause or the proper solution to avoid it.
 
Tom Kuffel
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Dana



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PostPosted: Fri Apr 30, 2010 4:07 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

At 12:25 AM 4/30/2010, The Kuffels wrote:
Quote:
Dana said:

<< << In a coordinated turn, the stall speed increases as a function of the
bank angle >>

Correct. >>

Not correct. This is only true in the special circumstance of maintaining altitude, ie increasing total lift, aka load factor.

I see your point, but... it's correct if you're maintaining altitude, but it's _also_ correct for a constant rate of descent, i.e. no vertical acceleration... which isn't happening in your 1g turn.

Quote:
The emphasis on this without equal emphasis on the special circumstance is *why* pilots in the stress of landing still stall by trying to increase their rate of turn with rudder alone (uncoordinated flight) and/or pulling back (increasing load factor). The certain antidote to this error is constant airspeed during landing maneuvers.... I don't dispute holding a constant airspeed in a turn will increase your rate of decent. But we are not talking about turns which last for minutes or even more than a few seconds. I strongly dispute the notion that any technique other than constant airspeed and coordinated flight independent of (less than aerobatic) bank angle is the proper way to avoid problems during the turn from base to final, particularly in situations of no or steady power or practicing same, which should be almost always.

OK. I'm not saying your technique isn't valid; I'm just speaking as an aeronautical engineer precisely defining the situation. In aero engineering most flight conditions, other than stability and control calculations, are analyzed steady state, which your 1G increasing rate of descent gliding turn is not. Letting the airplane slide (not slip; by "slide" I mean keeping the ball centered) out of a turn by letting the nose drop is indeed a good way to manage a gliding turn. Reducing the load factor also maintains energy since you're not holding high AOA which causes drag and slows you down even more.

I simply take exception to the notion that all will be well if you maintain constant airspeed. You say that avoidance of steep bank angle kills pilots who, trying to avoid an accelerated stall, instead spin out of a skid, and that's true, but it's only one side of the problem. On the other side, believing that all will be OK if you only maintain a constant airspeed can also get you into trouble... if a pilot does a 60 degree bank at 1.3Vs and _doesn't_ back off on the stick and let the nose drop, he _will_ experience an accelerated stall, which can be just as bad as the stall out of a skid.

So: Stall speed is a function of load factor, not (necessarily) bank angle. Load factor IS a function of bank angle, but only in coordinated, level or constant vertical speed, flight.

-Dana


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PostPosted: Fri Apr 30, 2010 7:47 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

This is not true. The lift vector on the wings has no idea what the gravity vector is doing. Go up and set a bank angle of 20 degrees and constant airspeed. You will find yourself in a steady state turn of 1 g. What will also happen is your rate of decent will increase. But this decent is not in a vacuum. The increase in your decent is actually slowed by the air such that several full circles are easily possible.. I've demonstrated this many times for people, even disbelieving fellow CFIs. (Are CFIs really people?) Now when doing the same thing at 60 degree bank things get real exciting very soon, even at only 1/4 circle, which may be Dana's point. But my point is this fact doesn't apply to the problem, its cause or the proper solution to avoid it.

Tom Kuffel
Quote:

Tom you said “Now when doing the same thing at 60 degree bank things get real exciting very soon, even at only 1/4 circle,” ok would you like to explain in further detail just how ex citing and in what way?

Boyd
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PostPosted: Fri Apr 30, 2010 3:53 pm    Post subject: Angle of Bank vs Stall Speed Reply with quote

Hi Boyd,
<< Tom you said “Now when doing the same thing at 60 degree bank things get real exciting very soon, even at only 1/4 circle,” ok would you like to explain in further detail just how ex citing and in what way? >>
Sure. In any 1 g turn the amount of lift used to make the turn is then not available to resist the force of earth's gravity. This means you will increase your rate of descent. In shallow bank turns the effect is small and not very apparent even after a full circle. At 60 degrees however the rate of descent increases to a dramatic amount by at least a half circle, sometimes sooner depending on aircraft aerodynamics and your personal definition of exciting.

But this is not the situation which kills pilots. Here we are talking about the descending quarter circle turn to final. Half way through the turn the pilot sees he is overshooting the runway path. What he should do is concentrate on maintaining the same airspeed, briefly increase his angle of bank, even up to 60 degrees if needed, and smoothly roll out. Doing this maintains a 1 g turn, ok a 1.1 g turn on rollout if one wants to quibble, which does not increase your stall speed for all practical purposes. You are at the increased bank angle for at most 1/8 of a circle.

But because "increased bank angle means increased stall speed" is buried in the back, dark recesses of our training too many pilots try to save the situation by fudging the turn, either with rudder (uncoordinated flight) or by pulling back (increased load factor).

My solution to this problem is the following basis for landing approaches. Opposite the approach end of the runway reduce power and set configuration (flaps and trim) to your desired approach speed. Maintain this speed *constantly* until at least you are established on final. Turns should normally be 20 - 30 degrees of bank. On turn to final the bank can be increased as described above for the time needed to complete the turn. This is guaranteed to not produce a stall or breathtaking rates of descent.

Within this framework there are lots of variables such as adjusting power or adjusting airspeed along the back side of the power curve after being established on final. But from the start of the approach descent until at least established on final the sure and certain way to avoid an unintended stall is constant airspeed control.

Again, go out to altitude and try some example quarter circle turns for yourself. Even at speeds unreasonably close to Vso you won't get even a nibble of a stall at angles of bank below aerobatic flight. Or come visit us in Whitefish and I'll demonstrate in an airplane easier to stall than a Kolb.

Best,

Tom

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PostPosted: Sat May 01, 2010 3:14 am    Post subject: Re: Angle of Bank vs Stall Speed Reply with quote

...But because "increased bank angle means increased stall speed" is buried in the back, dark recesses of our training too many pilots try to save the situation by fudging the turn, either with rudder (uncoordinated flight) or by pulling back (increased load factor)....

Tom is correct here and I believe that the primary reason for the last part, "pulling back (increased load factor)" is the more common and due largely to the pilot's noticing the increased descent rate when banking steeper and his natural response to halt the higher descent rate. If the approach trajectory is higher then the increased descent rate would not be so "scary" and thus less likely to elicit the "pulling back" response resulting in increased load factor and higher stall speed.

This brings me to one of the reasons that over the years I've adopted the practice of always (whenever possible) making a high approach and kill altitude only after I'm on stable short final. With my Slingshot this is very easy to accomplish. When I was flying an Allegro with rather high aspect ratio wings, it was a lot more difficult to get down in a short distance, but achievable though to a lessor degree.


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PostPosted: Sat May 01, 2010 7:53 am    Post subject: Angle of Bank vs Stall Speed Reply with quote

Quote:
>>>>>>>>>>>>>>>>>
Tom


But this is not the situation which kills pilots. Here we are talking about the descending quarter circle turn to final. Half way through the turn the pilot sees he is overshooting the runway path. What he should do is concentrate on maintaining the same airspeed, briefly increase his angle of bank, even up to 60 degrees if needed, and smoothly roll out. Doing this maintains a 1 g turn, ok a 1.1 g turn on rollout if one wants to quibble, which does not increase your stall speed for all practical purposes. You are at the increased bank angle for at most 1/8 of a circle.

I guess there is still one other option not yet discussed.…… ,go ahead and overshoot the centerline, stay at your current angle of bank and speed, make the turn to final a 100 to 105 deg turn and angle back to the centerline, then straighten up when on center. At the base to final turn you should be 400 to 500 ft agl and plenty of time and altitude for another few deg of turn.
During ppl training I did exactly what you recommend, and that is when my cfi deemed it necessary to do an extended lesson on accelerated stalls.

Or come visit us in Whitefish and I'll demonstrate in an airplane easier to stall than a Kolb.

That is the best offer I have heard all day. Hope you are not surprised when I take you up on that. Is my waypoint in the gps still good?

Boyd

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