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rsmith52
Joined: 16 Mar 2017
Posts: 15
Location: Crawford, CO
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 Posted: Sun Jan 31, 2021 10:38 am Post subject: LED question |
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I am installing dual lightspeed ignitions in my Bearhawk. 5100H1LC LEDs are speced as panel mounts to indicate when one of the ignitions is not powered. The LEDs are powered off a pin on the ignition output connectors. The LEDS are described as 1.8V low current, the red lead is indicated as positive. To test them I used a new AA battery reading 1.6V. I did not get even a faint glow, so wondering if they are bad or if they need the full 1.8V or more to produce visible output.
Rod
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kjashton(at)vnet.net
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| Posted: Sun Jan 31, 2021 11:37 am Post subject: LED question |
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The spec says “will operate off 5V to 12V without an external resistor". You just need more juice. See datasheet here https://www.digikey.com/en/products/detail/visual-communications-company-vcc/5100H1LC/59900
-Kent
| Quote: | On Jan 31, 2021, at 1:37 PM, Rod Smith <rodsmith52(at)yahoo.com> wrote:
I am installing dual lightspeed ignitions in my Bearhawk. 5100H1LC LEDs are speced as panel mounts to indicate when one of the ignitions is not powered. The LEDs are powered off a pin on the ignition output connectors. The LEDS are described as 1.8V low current, the red lead is indicated as positive. To test them I used a new AA battery reading 1.6V. I did not get even a faint glow, so wondering if they are bad or if they need the full 1.8V or more to produce visible output.
Rod
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user9253
Joined: 28 Mar 2008
Posts: 1927
Location: Riley TWP Michigan
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| Posted: Sun Jan 31, 2021 11:45 am Post subject: Re: LED question |
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Do NOT test an LED with a battery without a series resistor. Otherwise the
LED will be destroyed. You did not destroy yours because the battery voltage
was not high enough. But if the battery was 1.8 volts or more, the LED would
be destroyed without a series resistor. There are online calculators to
determine the resistor value to use.
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Joe Gores |
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user9253
Joined: 28 Mar 2008
Posts: 1927
Location: Riley TWP Michigan
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| Posted: Sun Jan 31, 2021 11:51 am Post subject: Re: LED question |
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I was wrong and Kent is right. The 5100H1LC has a Built-in resistor chip.
But if an LED does not have a built in resistor, then one must be added.
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