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slyck(at)frontiernet.net Guest
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dalewhelan
Joined: 11 Nov 2008 Posts: 105 Location: USA ARIZONA fountain hills
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Posted: Mon Sep 07, 2009 5:49 pm Post subject: Re: wing attach vector |
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I would like to know how to find out, I would like to guess 330 degrees
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_________________ Dale Whelan
503 powered Firestar II, Luscombe 8A
Projection, A simple and interesting Psychological concept |
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aslsa.rng(at)gmail.com Guest
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Posted: Mon Sep 07, 2009 6:04 pm Post subject: wing attach vector |
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Quote: | From "Stress Without Tears" by Tom Rhodes, Chapter 4, figure 6, the direction of the load at the spar attach comes straight in from the spar or in the original question here, 270 degrees. All other loads come into the fuselage at the strut attach fitting.
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Rick Girard
do not archive
On Mon, Sep 7, 2009 at 8:49 PM, dalewhelan <dalewhelan(at)earthlink.net (dalewhelan(at)earthlink.net)> wrote:
[quote]--> Kolb-List message posted by: "dalewhelan" <dalewhelan(at)earthlink.net (dalewhelan(at)earthlink.net)>
I would like to know how to find out, I would like to guess 330 degrees
--------
Dale Whelan
503 powered Firestar II
Projection, A simple and interesting Psychological concept
Read this topic online here:
http://forums.matronics.com/viewtopic.php?p=261970#261970
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jbhart(at)onlyinternet.ne Guest
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Posted: Tue Sep 08, 2009 8:55 am Post subject: wing attach vector |
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At 11:04 AM 9/7/09 -0400, you wrote:
Quote: |
Here's one to ponder. .. Maybe it has been covered before and I
missed it.
Assuming a compass of 360 degrees with 0/360 at the top and 90
outboard, where would the net
force be pushing on the front attach fitting? 325?
Jack Hart is our most analytical soul
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Bob,
I took some measurements off the FireFly so that I could run the
calculations. I did not consider dihedral, and assumed the wing horizontal.
Also, I assumed the main spar carried all the weight.
I calculated two cases. The first assumes the load is evenly distributed
over the entire wing and so the load was applied mid way from the wing tip
to the hole through the main spar tab. For the second case I assumed that
the outer 20% of the wing does not support any lift due to the air spilling
off the wing tip. Therefore the spar center of lift moved inward.
The cage hole reaction vector was found to be 195 degrees for the first case
and 187 degrees for the second case. When you think about it is reasonable.
With a strut design, most of the lift force is taken up by the strut. This
means that most of the lift force flows down to the lower strut anchoring
point on the cage and this point does most of the lifting. But the spar
between the strut attachment point to the cage is in compression. In the
FireFly configuration, the strut angle measures out to be close to 45
degrees to the wing. So the spar compression is almost equal to the lift.
With most of the lift supported by the strut, there is very little up load
at the spar cage attachment point. And so the vector comes out close to 180
degrees.
I hope this makes sense.
Jack B. Hart FF004
Winchester, IN
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aslsa.rng(at)gmail.com Guest
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Posted: Tue Sep 08, 2009 9:17 am Post subject: wing attach vector |
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Jack, Forgive me but under the reference frame where 0 /360 is up (parallel to lift) having the spar pin load at 180 (straight down) is just not obvious to me. Are we talking differing reference frames? If not, can you explain how the load coming in from the spar takes a hard 90 degree turn. I'm not saying you're wrong or trying to start a Florida discussion , I honestly just don't see it.
Rick Girard
do not archive
On Tue, Sep 8, 2009 at 12:55 PM, Jack B. Hart <jbhart(at)onlyinternet.net (jbhart(at)onlyinternet.net)> wrote:
[quote]--> Kolb-List message posted by: "Jack B. Hart" <jbhart(at)onlyinternet.net (jbhart(at)onlyinternet.net)>
At 11:04 AM 9/7/09 -0400, you wrote:
>--> Kolb-List message posted by: robert bean <slyck(at)frontiernet.net (slyck(at)frontiernet.net)>
>
>Here's one to ponder. .. Maybe it has been covered before and I
>missed it.
>Assuming a compass of 360 degrees with 0/360 at the top and 90
>outboard, where would the net
>force be pushing on the front attach fitting? 325?
>
>Jack Hart is our most analytical soul
Bob,
I took some measurements off the FireFly so that I could run the
calculations. I did not consider dihedral, and assumed the wing horizontal.
Also, I assumed the main spar carried all the weight.
I calculated two cases. The first assumes the load is evenly distributed
over the entire wing and so the load was applied mid way from the wing tip
to the hole through the main spar tab. For the second case I assumed that
the outer 20% of the wing does not support any lift due to the air spilling
off the wing tip. Therefore the spar center of lift moved inward.
The cage hole reaction vector was found to be 195 degrees for the first case
and 187 degrees for the second case. When you think about it is reasonable.
With a strut design, most of the lift force is taken up by the strut. This
means that most of the lift force flows down to the lower strut anchoring
point on the cage and this point does most of the lifting. But the spar
between the strut attachment point to the cage is in compression. In the
FireFly configuration, the strut angle measures out to be close to 45
degrees to the wing. So the spar compression is almost equal to the lift.
With most of the lift supported by the strut, there is very little up load
at the spar cage attachment point. And so the vector comes out close to 180
degrees.
I hope this makes sense.
Jack B. Hart FF004
Winchester, IN
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arget="_blank">http://www.matronics.com/Navigator?Kolb-List
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===========
[b]
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slyck(at)frontiernet.net Guest
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Posted: Tue Sep 08, 2009 10:42 am Post subject: wing attach vector |
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Rick, Jack has been doing some inverted flight.BB
On 8, Sep 2009, at 1:17 PM, Richard Girard wrote:
[quote]Jack, Forgive me but under the reference frame where 0 /360 is up (parallel to lift) having the spar pin load at 180 (straight down) is just not obvious to me. Are we talking differing reference frames? If not, can you explain how the load coming in from the spar takes a hard 90 degree turn. I'm not saying you're wrong or trying to start a Florida discussion , I honestly just don't see it.
Rick Girard
do not archive
On Tue, Sep 8, 2009 at 12:55 PM, Jack B. Hart <jbhart(at)onlyinternet.net (jbhart(at)onlyinternet.net)> wrote:
Quote: | --> Kolb-List message posted by: "Jack B. Hart" <jbhart(at)onlyinternet.net (jbhart(at)onlyinternet.net)>
At 11:04 AM 9/7/09 -0400, you wrote:
>--> Kolb-List message posted by: robert bean <slyck(at)frontiernet.net (slyck(at)frontiernet.net)>
>
>Here's one to ponder. .. Maybe it has been covered before and I
>missed it.
>Assuming a compass of 360 degrees with 0/360 at the top and 90
>outboard, where would the net
>force be pushing on the front attach fitting? 325?
>
>Jack Hart is our most analytical soul
Bob,
I took some measurements off the FireFly so that I could run the
calculations. I did not consider dihedral, and assumed the wing horizontal.
Also, I assumed the main spar carried all the weight.
I calculated two cases. The first assumes the load is evenly distributed
over the entire wing and so the load was applied mid way from the wing tip
to the hole through the main spar tab. For the second case I assumed that
the outer 20% of the wing does not support any lift due to the air spilling
off the wing tip. Therefore the spar center of lift moved inward.
The cage hole reaction vector was found to be 195 degrees for the first case
and 187 degrees for the second case. When you think about it is reasonable.
With a strut design, most of the lift force is taken up by the strut. This
means that most of the lift force flows down to the lower strut anchoring
point on the cage and this point does most of the lifting. But the spar
between the strut attachment point to the cage is in compression. In the
FireFly configuration, the strut angle measures out to be close to 45
degrees to the wing. So the spar compression is almost equal to the lift.
With most of the lift supported by the strut, there is very little up load
at the spar cage attachment point. And so the vector comes out close to 180
degrees.
I hope this makes sense.
Jack B. Hart FF004
Winchester, IN
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arget="_blank">http://www.matronics.com/Navigator?Kolb-List
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le, List Admin.
="_blank">http://www.matronics.com/contribution
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jbhart(at)onlyinternet.ne Guest
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Posted: Tue Sep 08, 2009 2:14 pm Post subject: wing attach vector |
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You guys got me. I calculated everything with zero to the right, and forgot to rotate to your reference system, one would have add 90 degrees. The cage hole reaction vector was found to be 285 degrees for the first case and 277 degrees for the second case.
Jack B. Hart FF004
Winchester, IN
At 11:04 AM 9/7/09 -0400, you wrote:
Quote: |
Here's one to ponder. .. Maybe it has been covered before and I
missed it.
Assuming a compass of 360 degrees with 0/360 at the top and 90
outboard, where would the net
force be pushing on the front attach fitting? 325?
Jack Hart is our most analytical soul
|
Bob,
I took some measurements off the FireFly so that I could run the
calculations. I did not consider dihedral, and assumed the wing horizontal.
Also, I assumed the main spar carried all the weight.
I calculated two cases. The first assumes the load is evenly distributed
over the entire wing and so the load was applied mid way from the wing tip
to the hole through the main spar tab. For the second case I assumed that
the outer 20% of the wing does not support any lift due to the air spilling
off the wing tip. Therefore the spar center of lift moved inward.
The cage hole reaction vector was found to be 195 degrees for the first case
and 187 degrees for the second case. When you think about it is reasonable.
With a strut design, most of the lift force is taken up by the strut. This
means that most of the lift force flows down to the lower strut anchoring
point on the cage and this point does most of the lifting. But the spar
between the strut attachment point to the cage is in compression. In the
FireFly configuration, the strut angle measures out to be close to 45
degrees to the wing. So the spar compression is almost equal to the lift.
With most of the lift supported by the strut, there is very little up load
at the spar cage attachment point. And so the vector comes out close to 180
degrees.
I hope this makes sense.
Jack B. Hart FF004
Winchester, IN
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slyck(at)frontiernet.net Guest
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Posted: Tue Sep 08, 2009 2:42 pm Post subject: wing attach vector |
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That's an agreeable (and believable) calculation. If the force at
that point was only tension the beam between could be
a skinny little tube. The square tube on the MkII has a reason. -
not sure what the FF has there.
The forward cabin area is subject to reversals of thrust, such as
during a hard landing when the engine weight and wing forces give
a downward (and outward) whack.
Thanks Jack.
BB
On 8, Sep 2009, at 7:23 PM, Jack B. Hart wrote:
Quote: |
<jbhart(at)onlyinternet.net>
You guys got me. I calculated everything with zero to the right,
and forgot to rotate to your reference system, one would have add
90 degrees. The cage hole reaction vector was found to be 285
degrees for the first case and 277 degrees for the second case.
Jack B. Hart FF004
Winchester, IN
At 11:04 AM 9/7/09 -0400, you wrote:
>
>
> Here's one to ponder. .. Maybe it has been covered before and I
> missed it.
> Assuming a compass of 360 degrees with 0/360 at the top and 90
> outboard, where would the net
> force be pushing on the front attach fitting? 325?
>
> Jack Hart is our most analytical soul
Bob,
I took some measurements off the FireFly so that I could run the
calculations. I did not consider dihedral, and assumed the wing
horizontal.
Also, I assumed the main spar carried all the weight.
I calculated two cases. The first assumes the load is evenly
distributed
over the entire wing and so the load was applied mid way from the
wing tip
to the hole through the main spar tab. For the second case I
assumed that
the outer 20% of the wing does not support any lift due to the air
spilling
off the wing tip. Therefore the spar center of lift moved inward.
The cage hole reaction vector was found to be 195 degrees for the
first case
and 187 degrees for the second case. When you think about it is
reasonable.
With a strut design, most of the lift force is taken up by the
strut. This
means that most of the lift force flows down to the lower strut
anchoring
point on the cage and this point does most of the lifting. But the
spar
between the strut attachment point to the cage is in compression.
In the
FireFly configuration, the strut angle measures out to be close to 45
degrees to the wing. So the spar compression is almost equal to
the lift.
With most of the lift supported by the strut, there is very little
up load
at the spar cage attachment point. And so the vector comes out
close to 180
degrees.
I hope this makes sense.
Jack B. Hart FF004
Winchester, IN
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